12x^2-104x-150=0

Solution for 12x^2-104x-150=0 equation:

12x^2-104x-150=0

a = 12; b = -104; c = -150;
Δ = b2-4ac
Δ = -1042-4·12·(-150)
Δ = 18016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{18016}=\sqrt{16*1126}=\sqrt{16}*\sqrt{1126}=4\sqrt{1126}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-104)-4\sqrt{1126}}{2*12}=\frac{104-4\sqrt{1126}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-104)+4\sqrt{1126}}{2*12}=\frac{104+4\sqrt{1126}}{24}
$